高三化學(xué)“熱化學(xué)反應(yīng)”方程式

編輯: 逍遙路 關(guān)鍵詞: 高三學(xué)習指導(dǎo) 來源: 高中學(xué)習網(wǎng)

如何提高學(xué)習率,需要我們從各方面去努力。小編為大家整理了高三化學(xué)熱化學(xué)反應(yīng)方程式,希望對大家有所幫助。

C(s)+1/2O2(g)==CO(g); △H=-393.5kJ/mol

C(s)+O2(g)==CO2(g); △H=-110.5kJ/mol

CO(g)+1/2O2(g)==CO2(g);△H=-283.0kJ/mol

H2(g)+1/2O2(g)==H2O(g);△H=-241.8kJ/mol

H2(g)+1/2O2(g)==H2O(l);△H=-285.8kJ/mol

2H2(g)+O2(g)==2H2O(g);△H=-483.6kJ/mol

2H2(g)+O2(g)==2H2O(l);△H=-571.6kJ/mol

CH4(g)+2O2(g)==CO2(g)+2H2O(l);△H=-890.3kJ/mol

C8H18(l)+12.5O2(g)==8CO2(g)+9H2O(l);△H=-5518kJ/mol

C6H12O6(s)+6O2(g)==6CO2(g)+6H2O(l);△H=-2800kJ/mol

N2H4(g)+O2(g)==N2(g)+2H2O(g);△H=-534kJ/mol

S(s)+O2(g)==SO2(g); △H=-297kJ/mol

FeS2(s)+11/4O2(g)==1/2Fe2O3(s)+2SO2(g);△H=-853kJ/mol

SO2(s)+1/2O2(g)==SO3(g);△H=-98.3kJ/mol

SO3(g)+H2O(l)==H2SO4(l);△H=-130.8kJ/mol

H2(g)+Cl2(g)==2HCl(g);△H=-184.6kJ/mol

C(s)+H2O(g)==H2(g)+CO2(g);△H=+131.5kJ/mol

3H2(g)+N2(g)==2NH3(g);△H=-92.2kJ/mol

2O2(g)+N2(g)==2NO2(g);△H=+68kJ/mol

O2(g)+N2(g)==2NO(g);△H= -kJ/mol

O2(g)+2NO(g)==2NO2(g);△H= -kJ/mol

2NO2(g)==N2O4(g);△H= -kJ/mol

Cu(s)+1/2O2(g)==CuO(s);△H=-157kJ/mol

CaCO3(s)+==CaO(s)+CO2(g);△H=+1777kJ/mol

C(石墨) + O2(g) === CO2(g); △H = -393.51kJ mol-1

C(金剛石) + O2(g) === CO2(g); △H = -395.41kJ mol-1

C(石墨) ===C(金剛石); △H = +1.9kJ mol-1

NaOH(aq)+HCl(aq)=NaCl(aq)+H2O(l);△H=-57.3kJ/mol

KOH(aq)+HNO3(aq)=NaNO3(aq)+H2O(l);△H=-57.3kJ/mol

NaOH(aq)+1/2H2SO4(aq)=1/2Na2SO4(aq)+H2O(l);△H=-57.3kJ/mol

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